Final answer:
The car would take approximately b) 180 feet.
Step-by-step explanation:
The stopping distance of a car can be determined using the equation d = v²/2a, where d is the stopping distance, v is the initial velocity, and a is the deceleration. Given that the car is coming to a stop, its final velocity (u) is 0 ft/sec. Assuming a uniform deceleration, we can use the equation v²= u²+2as to find a, the deceleration.
Rearranging the equation, a = v²/2s, where s is the stopping distance.
Substituting the values, a= (90ft/sec)²/2d
To find d, rearrange the stopping distance formula: d = v²/2a
d = (90ft/sec)²/ 2(90ft/sec)²/2d
Simplifying this expression yields d ≈ 180 feet
The car traveling at 90 ft/sec would require approximately 180 feet to come to a stop. This corresponds to option b) as the correct answer, indicating that the car's stopping distance is crucially influenced by both its initial velocity and the deceleration it experiences.