Question

4.000 x 10^3 L of propane gas is held in a tank at 25 °C. The tank has a moveable diaphragm to keep the pressure constant at 200 kPa. If the temperature falls to -5 °C on a cold winter day, what volume will the gas occupy?

Answer 1

1) list your givens and convert if necessary

P₁ = 200 kPa

V₁ = 4.000 ×
`10^(3)` L

T₁ = 298.15 K

P₂ = 200 kPa

V₂ = ?

T₂ = 268.15 K

2) rearrange formula

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))\\\\V_(2)=(T_(2)P_(1)V_(1))/(P_(2)T_(1))`

3) solve

`V_(2)=((268.15\ K)(200\ kPa)(4.000\ x\ 10^(3) L))/((200\ kPa)(298.15\ K))`

V₂ = 3597.518028 L (round as you wish)