The solution to the system of equations using the elimination method is a = -2, b = 4, c = 3.
To solve the given system of equations using the elimination method, we can follow these steps:
Write both equations in standard form.
Multiply one or both equations by constants, if needed, to make the coefficients of a variable opposites.
Add or subtract the equations to eliminate a variable.
Solve for the remaining variable.
Substitute the value found back into one of the original equations to solve for the other variable.
Given the system:
6a+ 5b+c=5
5a3b-5c = -29
-2a-4b2c= -12
We can start by eliminating the variable ( c ). To do this, we can multiply the first equation by 2 and the third equation by 5, and then add the resulting equations to eliminate ( c ).
After solving for ( a ) and ( b ), we can substitute the values back into one of the original equations to solve for the remaining variable.
The solution to the system of equations using the elimination method is a = -2, b = 4, c = 3.