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Solve the following initial-value problems starting from y₀ = 8.
dy/dt = e⁵ᵗ

User Runforever
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1 Answer

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Final answer:

To solve the initial-value problem dy/dt = e^5t, integrate both sides with respect to t, substitute the initial condition y₀ = 8, and solve for the constant of integration.

Step-by-step explanation:

To solve the initial-value problem dy/dt = e^5t, we can integrate both sides with respect to t. Since the derivative of e^5t is e^5t itself, the equation becomes:

∫dy = ∫e^5t dt

Integrating both sides gives y = (1/5)e^5t + C, where C is the constant of integration. To find the specific solution, we can use the initial condition y₀ = 8. Substituting this value into the equation:

8 = (1/5)e^5(0) + C

8 = (1/5) + C

C = 8 - 1/5 = 39/5

Therefore, the solution to the initial-value problem is y = (1/5)e^5t + 39/5.

User Mayou
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