Question

What concentration of SO₂⁴⁻ that remains in solution given "a solution of 120 mL of 0.200 M KOH is mixed with a solution of 280 mL of 0.230 M NiSO4" and the balanced equation

2KOH(aq)+NiSO₄(aq)→K₂SO₄(aq)+Ni(OH)₂(s)?

Answer 1

To find the concentration of SO4^2- that remains in solution, you can calculate the moles of SO4^2- in the initial solution and divide it by the final volume of the solution. Given the initial solution of 120 mL of 0.200 M KOH and the final volume of 400 mL, you can calculate the moles of KOH and use the balanced equation to determine the moles of SO4^2-. Finally, divide the moles of SO4^2- by the final volume to find the concentration.

Step-by-step explanation:

To determine the concentration of SO42- that remains in solution, we need to calculate the number of moles of SO42- in the initial solution and divide it by the final volume of the solution.

Given that the initial solution is 120 mL of 0.200 M KOH and the final volume is 400 mL (120 mL + 280 mL), we can first calculate the number of moles of KOH:

Moles of KOH = volume of KOH solution (L) x concentration of KOH (M)

Moles of KOH = 0.120 L x 0.200 M = 0.024 mol

Since the balanced equation is 2KOH(aq) + NiSO4(aq) → K2SO4(aq) + Ni(OH)2(s), we can see that for every 2 moles of KOH, 1 mole of SO42- is produced.

So the moles of SO42- in the initial solution is 0.024/2 = 0.012 mol.

Finally, we divide the moles of SO42- by the final volume of the solution to find the concentration:

Concentration of SO42- = moles of SO42- / final volume of solution (L)

Concentration of SO42- = 0.012 mol / 0.400 L = 0.03 M.