Question

When an ion accelerates through a potential difference of -1950 V , its electric potential energy decreases by 6.02×10⁻¹⁶ J . what is the charge of the ion?

Answer 1

The charge of the ion is -3.08×10-19 C.

Step-by-step explanation:

When an ion accelerates through a potential difference, its electric potential energy decreases. The electric potential energy change can be calculated using the formula ∆PE = qV, where ∆PE is the change in potential energy, q is the charge of the ion, and V is the potential difference. In this case, ∆PE = 6.02×10-16 J and V = -1950 V. Rearranging the formula, we can solve for q:

∆PE = qV

6.02×10-16 J = q(-1950 V)

q = 6.02×10-16 J / (-1950 V)

q = -3.08×10-19 C

The charge of the ion is -3.08×10-19 C.