Final answer:
The temperature of the gas increases by about 6% during the process 1→3→6, following the principles of the ideal gas law where an increase in pressure at constant volume indicates an increase in temperature.
Step-by-step explanation:
During the process 1→3→6, the temperature of the gas increases. This is inferred from the details provided that describe a thermodynamic cycle beginning at a certain pressure and volume, changing to an equal pressure at a reduced volume, and finally increasing in pressure at the same reduced volume.
According to the ideal gas law (PV=nRT), when the volume is constant (an isochoric process), a rise in pressure corresponds to a rise in temperature since the amount of substance (n) and the gas constant (R) are constants.
As the final pressure is about 6% greater than the initial pressure, the final temperature will also be about 6% greater.
In a thermodynamic process where the gas changes from state 1 to state 3 and then to state 6, the temperature of the gas increases. This increase in temperature is due to the increase in kinetic energy of the gas molecules. As a result, the pressure of the gas also increases.