Final answer:
The voltage can be calculated using the formula V = Q/C, where V is the voltage, Q is the charge, and C is the capacitance. The capacitance can be calculated using the formula C = ε₀A/d, where ε₀ is the permittivity of free space, A is the area, and d is the distance between the plates. Plugging in the given values, the voltage between the plates of the capacitor is 3640 V.
Step-by-step explanation:
The voltage between the plates of a capacitor can be calculated using the formula V = Q/C, where V is the voltage, Q is the charge on the plates, and C is the capacitance. The capacitance of a parallel-plate capacitor can be determined using the formula C = ε₀A/d, where ε₀ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.
In the given question, the distance between the plates is 0.40 mm, which is equal to 0.40 x 10⁻³ m. The charge on the plates is 0.020 µC, which is equal to 0.020 x 10⁻⁶ C. The voltage is 250 V. Plugging these values into the formulas, we can calculate the capacitance: C = (8.85 x 10⁻¹² F/m) * (0.25 m² / 0.40 x 10⁻³ m) = 5.5 x 10⁻¹⁰ F. Finally, we can use the formula V = Q/C to find the voltage: V = (0.020 x 10⁻⁶ C) / (5.5 x 10⁻¹⁰ F) = 3640 V.