Final answer:
Mixing potassium bromide with lead(II) nitrate results in a chemical reaction that forms an insoluble precipitate of lead(II) bromide, while potassium nitrate remains dissolved in the solution.
Step-by-step explanation:
When potassium bromide is mixed with lead(II) nitrate, a double-replacement reaction occurs, leading to the formation of lead(II) bromide as a precipitate. This is due to lead(II) bromide being an exception to the general solubility rules, making it insoluble in water. Consequently, the potassium and nitrate ions become spectator ions, not participating in the formation of the precipitate. The reaction can be represented by the net ionic equation:
Pb^{2+} (aq) + 2Br^- (aq) → PbBr_2 (s)
This implies that the other product of the reaction, likely to be potassium nitrate, remains dissolved in the solution, given that it is generally soluble as per solubility rules.