Question

A fireworks shell is accelerated from rest to a velocity of 51.0 m/s over a distance of 0.270 m. What is the acceleration of the fireworks shell, and what external forces are acting on it?

Answer 1

The acceleration of the fireworks shell is 188.89 m/s². The external forces acting on the shell during acceleration include the force applied by the fireworks mortar and the force of gravity.

Step-by-step explanation:

The acceleration of the fireworks shell can be calculated using the equation:

acceleration = (final velocity - initial velocity) / distance

Given that the initial velocity is 0 m/s, the final velocity is 51.0 m/s, and the distance is 0.270 m, we can substitute these values into the equation:

acceleration = (51.0 m/s - 0 m/s) / 0.270 m

Simplifying the equation gives us:

acceleration = 188.89 m/s²

The external forces acting on the shell during acceleration can include the force applied by the fireworks mortar and the force of gravity. The force applied by the fireworks mortar propels the shell forward, while the force of gravity pulls the shell downward. These forces combine to accelerate the shell.