Question

The magnitude of a uniform electric field between the two plates is about 2 × 10^5 N/C. If the distance between these plates is 0.1 cm, find the potential difference between the plates. Answer in units of V.

Answer 1

The potential difference between the plates in a uniform electric field with a strength of 2 × 10^5 N/C and a plate separation of 0.1 cm is 200 V.

Step-by-step explanation:

The question involves calculating the potential difference between two plates in a uniform electric field. The electric field strength (E) is given as 2 × 105 N/C, and the distance (d) between the plates is 0.1 cm, which should be converted to meters to maintain SI units, making it 0.001 m. Using the formula ΔV = E × d, where ΔV is the potential difference, we can calculate that as:

ΔV = (2 × 105 N/C) × (0.001 m) = 200 V.

Therefore, the potential difference between the plates is 200 volts.