Question

A hose lying on the ground has water coming out of it at a speed of 5.4 meters per second. You lift the nozzle of the hose to a height of 1.3 meters above the ground. At what speed does the water now come out of the hose?

Answer 1

When the nozzle of the hose is lifted, the new speed of the water can be calculated using the equation V2 = sqrt(V1^2 + 2gh), where V1 is the initial speed, g is the acceleration due to gravity, and h is the change in height.

Step-by-step explanation:

When the nozzle of the hose is lifted to a height of 1.3 meters above the ground, the speed at which the water comes out of the hose will change. This change in speed can be calculated using the principles of conservation of energy.

To determine the new speed of the water, we can make use of the equation: V2 = sqrt( V1^2 + 2gh) where V2 is the final speed, V1 is the initial speed, g is the acceleration due to gravity, and h is the change in height. Plugging in the values, we get:

V2 = sqrt(5.4^2 + 2 * 9.8 * 1.3)

V2 = sqrt(29.16 + 25.48)

V2 = sqrt(54.64)

V2 ≈ 7.4 meters per second