Final answer:
In this case,
is indeed in the column space of A and we can conclude that the system Ax = B is consistent.
Step-by-step explanation:
To determine if b is in the column space of A, we can check if the equation Ax = b has a solution.
Let's calculate the column space of A. The column space of a matrix A is the set of all possible linear combinations of the columns of A. In other words, it is the span of the columns of A.
Given
and
, we can rewrite the equation Ax = B as a system of equations:
1x + 2y = 4
2x + 4y = 8
We can simplify the second equation by dividing it by 2:
x + 2y = 4
Notice that the first equation is a multiple of the second equation. This means that the two equations are equivalent and represent the same line in the xy-plane.
Since the equations are equivalent, they have infinitely many solutions and the system is consistent. Therefore,
is in the column space of A.
In summary:
-
is in the column space of A.
- The system Ax = B is consistent.
Your question is incomplete, but most probably the full question was:
For each of the following choices of A and b, determine whether b is in the column space of A and state the consistency of the system Ax = B.
![A=\left[\begin{array}{ccc}1&2 \\2&4\\\end{array}\right]](https://img.qammunity.org/2024/formulas/business/high-school/9d0it3k2iv0qhd3m6mv5gz33yncig9pdy8.png)
![B= \left[\begin{array}{ccc}4\\8\\\end{array}\right]](https://img.qammunity.org/2024/formulas/business/high-school/71nwwgdnoewd4cyvoztdumypisxvj6oi1w.png)