Final answer:
The question as stated is ambiguous because it conflates the concept of the rank of a matrix with solving a quadratic equation. Assuming the intent is to solve the quadratic equation x² + 0.00088x - 0.000484 = 0, the quadratic formula can be used to find the two possible values of x.
Step-by-step explanation:
The question involves finding all values of x that make the rank of a matrix equal to 2. However, the question seems to be incorrectly stated, as there is no clear connection between the rank of a matrix and the provided quadratic equation. Normally, the rank of a matrix refers to the number of linearly independent rows or columns and is not directly related to the solution of a quadratic equation. In this case, it appears that we are supposed to solve the quadratic equation x² + 0.00088x - 0.000484 = 0.
To solve this quadratic equation, we use the quadratic formula:
x = [-b ± √(b² - 4ac)] / (2a)
Here, a = 1, b = 0.00088, and c = -0.000484. Plugging these values into the formula, we perform the calculation step:
x = [-0.00088 ± √(0.00088² - 4(1)(-0.000484))] / (2(1))
Performing the calculation step will yield two real values for x, which are the solutions to the equation.