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A 0.50 kg soccer ball is kicked straight up into the air at 14 m/s. Determine the maximum height that it reaches. Assume friction is negligible.

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Final answer:

The maximum height that the soccer ball reaches is 9.8 meters.

Step-by-step explanation:

To determine the maximum height that the soccer ball reaches, we can use the kinematic equations of motion. Since the ball is kicked straight up into the air, its vertical motion can be modeled using the equation:

vf^2 = vi^2 + 2ad

Where vf is the final velocity (0 m/s), vi is the initial velocity (14 m/s), a is the acceleration (g, the acceleration due to gravity which is approximately 9.8 m/s^2), and d is the displacement (maximum height). Rearranging the equation, we can solve for d:

d = (vf^2 - vi^2)/(2a)

Plugging in the values, we get:

d = (0 - (14^2))/(2 * -9.8)

d = 9.8 m

Therefore, the maximum height the soccer ball reaches is 9.8 meters.

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