Final answer:
The electric field strength between two charged rings can be calculated using Coulomb's law. In this case, the rings are charged with 50.0 nC each, and they are 15.0 cm apart. Using the given values, the electric field strength between the two charged rings is approximately 1.26 x 10^25 N/C.
Step-by-step explanation:
The electric field strength between two charged rings can be calculated using Coulomb's law. Coulomb's law states that the electric field strength between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
In this case, the rings are charged with 50.0 nC each, and they are 15.0 cm apart. The diameter of the rings is 10 cm, which means the radius is 5 cm. To calculate the electric field strength, we can use the formula:
Electric field strength = (Charge of one ring * Charge of the other ring) / (4πε₀ * Distance between the rings squared)
By substituting the given values, we get:
Electric field strength = (50.0 nC * 50.0 nC) / (4πε₀ * 0.15 m)
Electric field strength = (2500 nC²) / (0.60πε₀)
Using the value of ε₀ (vacuum permittivity) as 8.854 x 10^-12 C²/Nm², we can substitute it into the equation:
Electric field strength = (2500 nC²) / (0.60 * π * 8.854 x 10^-12 C²/Nm²)
Electric field strength ≈ 1.26 x 10^25 N/C
Therefore, the electric field strength between the two charged rings is approximately 1.26 x 10^25 N/C.