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A bicyclist traveling at 10 m/s slows down to turn a corner. After completing the turn, the bicyclist then has a speed of 7.0 m/s at an angle of 90° to the original direction. If it takes 7.0 s to complete the turn, what is the magnitude of the bicyclist's average acceleration?

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Final answer:

The magnitude of the bicyclist's average acceleration is 0.43 m/s².

Step-by-step explanation:

The average acceleration of the bicyclist can be calculated using the formula:

average acceleration = (change in velocity) / (time taken)

First, we need to find the change in velocity. The initial velocity is 10 m/s and the final velocity is 7.0 m/s. So, the change in velocity is 10 m/s - 7.0 m/s = 3.0 m/s.

Next, we divide the change in velocity by the time taken, which is 7.0 seconds:

average acceleration = 3.0 m/s / 7.0 s = 0.43 m/s²

Therefore, the magnitude of the bicyclist's average acceleration is 0.43 m/s².

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