Question

Ten grams (10.0) of acetic acid (CH3COOH) is dissolved in 500.0 ml of solution. What molarity results?

Answer 1

The molarity of the acetic acid solution is 0.3328 M.

Step-by-step explanation:

To find the molarity of the acetic acid solution, we need to use the equation:

Molarity (M) = moles of solute / volume of solution (in liters)

First, we convert the mass of acetic acid to moles using its molar mass:

(10.0 g CH3COOH) / (60.05 g/mol CH3COOH) = 0.1664 mol CH3COOH

Then, we divide the moles by the volume of the solution:

Molarity = 0.1664 mol / 0.5000 L = 0.3328 M