Final answer:
To prepare 1 liter of 2% saline solution, you would need approximately 85.47mL of a 23.4% sodium chloride solution and 914.53mL of sterile water for injection, following the dilution calculation using the formula C1V1 = C2V2.
Step-by-step explanation:
To make 1 liter of 2% saline solution from a 23.4% sodium chloride solution, you will need to perform a dilution calculation. A 2% solution means 2g of sodium chloride is present in every 100mL of the solution. Therefore, for 1 liter (1000mL), you need 20g of sodium chloride.
Using the formula C1V1 = C2V2, where C1 is the concentration of the initial solution (23.4%), V1 is the volume of the initial solution required, C2 is the desired concentration (2%), and V2 is the final volume of the solution (1 liter or 1000mL), you can solve for V1.
First convert the percentages into decimals by dividing by 100:
- C1 = 23.4 / 100 = 0.234
- C2 = 2 / 100 = 0.02
Now plug these values into the formula:
0.234V1 = 0.02(1000)
V1 = (0.02 × 1000) / 0.234
V1 ≈ 85.47 mL
This is the volume of 23.4% solution needed. To calculate the volume of sterile water needed, subtract V1 from the final volume required:
1000mL - 85.47mL ≈ 914.53mL
Therefore, you need approximately 85.47mL of 23.4% sodium chloride solution and 914.53mL of sterile water for injection to prepare 1 liter of 2% saline solution.