Final answer:
The amount of ammonia (NH3) produced from 30.0 grams of nitrogen (N2) can be calculated using stoichiometry, taking into account the balanced chemical equation, the molar mass of the reactants, and the product.
Step-by-step explanation:
To find out how many grams of ammonia (NH3) are formed when 30.0 grams of nitrogen (N2) is reacted with excess hydrogen (H2), we'll follow a series of stoichiometric calculations.
Step by Step Solution:
- Determine the molar mass of nitrogen gas (N2) which is 28.02 g/mol.
- Calculate the number of moles of N2: number of moles = mass (g) ÷ molar mass (g/mol).
- According to the balanced equation N2(g) + 3H2(g) → 2NH3(g), 1 mole of nitrogen reacts to produce 2 moles of ammonia.
- Find out the moles of NH3 produced: 2 moles NH3 are produced per mole N2.
- Calculate the molar mass of ammonia (NH3) which is 17.03 g/mol.
- Finally, convert the moles of NH3 to grams: mass (g) = number of moles * molar mass (g/mol).
After solving, you'll know the grams of ammonia produced from the given amount of nitrogen.