Final answer:
The capacitance of the parallel-plate capacitor is 1.49 x 10^-10 F, and the electric field between the plates is 8.57 x 10^3 V/m.
Step-by-step explanation:
To determine the capacitance of a parallel-plate capacitor, we can use the formula C = ε0 * A / d, where C is the capacitance, ε0 is the permittivity of free space, A is the area of the plates, and d is the distance between the plates. In this case, the area of each plate is (1.40 cm)2, and the distance between the plates is given as 1.40 mm (since the plates are square, the distance between the plates is equal to the edge length). The permittivity of free space, ε0, is approximately 8.854 x 10-12 F/m. Plugging in these values, we find:
C = (8.854 x 10-12 F/m) * (0.014 m)2 / (0.0014 m) = 1.49 x 10-10 F
To determine the electric field between the plates, we can use the formula E = V / d, where E is the electric field, V is the potential difference between the plates, and d is the distance between the plates. In this case, the potential difference between the plates is given as 12.0 V, and the distance between the plates is given as 1.40 mm. Plugging in these values, we find:
E = 12.0 V / 0.0014 m = 8.57 x 103 V/m