Question

When two point charges of equal magnitude q are held a distance d apart, what is the electric potential (v) at points along the line passing through both charges, taking v=0 at infinity?

Answer 1

The electric potential (v) at points along the line passing through two point charges of equal magnitude q and distance d apart can be calculated using the equation: V = (k * q) / d

Step-by-step explanation:

The electric potential (v) at points along the line passing through two point charges of equal magnitude q and distance d apart can be calculated using the equation:

V = (k * q) / d

where V is the electric potential, k is the Coulomb constant (9 x 10^9 Nm^2/C^2), q is the magnitude of the charges, and d is the distance between the charges.

For example, if the charges are both +2C and the distance between them is 0.5m:

1. Calculate k * q: (9 x 10^9 Nm^2/C^2) * 2C = 18 x 10^9 Nm^2/C
2. Divide the result by d: (18 x 10^9 Nm^2/C) / 0.5m = 36 x 10^9 V/m

Therefore, the electric potential at points along the line passing through the two charges is 36 x 10^9 V/m.