Question

Two charged particles are placed along the x-axis. The first particle has a charge q1 = q and is at the origin. The second has a charge q2 = -2q and is at x = d = 8.90 cm.

Answer 1

The electric field of the +q particle at the same distance is E = kq/r^2, and the force it exerts on the +2q particle is F = qE, where E is the electric field.

Step-by-step explanation:

The electric field of a charged particle at a certain distance is given by the formula E = kQ/r^2, where E is the electric field, k is the Coulomb's constant, Q is the charge, and r is the distance. In this case, the electric field of the +q particle at the same distance would be the same as the electric field of a charge q at that distance, which is E = kq/r^2. To find the force exerted by the +q particle on the +2q particle, we use the formula F = qE, where F is the force and E is the electric field. Substituting the electric field equation, we get F = q(kq/r^2).