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In how many ways can a selection be made if at least one Sony component is to be included?

User Eric Huang
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Final answer:

To find the number of ways a selection can be made if at least one Sony component is to be included, we can use the principle of inclusion-exclusion. First, we find the total number of selections possible, which is the number of ways to select from all the components. Then, we subtract the number of selections in which no Sony component is included. This gives us the number of ways to select at least one Sony component.

Step-by-step explanation:

To find the number of ways a selection can be made if at least one Sony component is to be included, we can use the principle of inclusion-exclusion. First, we find the total number of selections possible, which is the number of ways to select from all the components. Then, we subtract the number of selections in which no Sony component is included. This gives us the number of ways to select at least one Sony component.

Let's say there are n total components and m of them are Sony components. The total number of selections possible is 2^n (each component can either be included or not included). The number of selections with no Sony component is 2^(n-m) (as we are excluding all the Sony components from the selection).

Therefore, the number of ways to select at least one Sony component is 2^n - 2^(n-m). This expression can be simplified further, but it depends on the given values of n and m.

User Dsnunez
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