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Vectors A⃗ and B⃗ have scalar product -7.00, and their vector product has magnitude what? Determine the scalar product and vector product, and calculate the angle between these two vectors.

User PeteH
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Final answer:

The magnitude of the vector product of vectors A and B cannot be determined without additional information. The scalar product provided (-7.00) must be used in conjunction with the magnitudes of A and B to calculate the angle between them, thereafter determining the magnitude of the vector product.

Step-by-step explanation:

If vectors A and B have a scalar product (dot product) of -7.00, then the magnitude of their vector product (cross product) would depend on the angle between the two vectors. The scalar product is given by A·B = AB cos θ, where θ is the angle between the vectors and A and B are the magnitudes of the vectors. According to the information given, A·B = -7.00.

To find the vector product's magnitude, we use the formula |A×B| = AB sin θ. However, we don't have enough information to calculate it directly. First, we must find the angle between the two vectors. Doing so involves rearranging the scalar product formula to solve for cos θ, and then calculating the vector product using sin θ derived from the angle found.

Without the magnitudes of A and B, or the angle between them, we cannot determine the magnitude of the vector product directly from this information. However, if the magnitudes and the scalar product are known, we can find θ using cos θ = − 7.00 / (AB), then find the magnitude of the vector product using sin θ.

User Rourke
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