Final answer:
The mole to mole ratio between oxygen (O₂) and carbon dioxide (CO₂) in the combustion of propane (C₃H₈) is 5:3, as indicated by the coefficients in the balanced chemical equation.
Step-by-step explanation:
The mole to mole ratio between oxygen (O₂) and carbon dioxide (CO₂) in the combustion of propane (C₃H₈) is taken directly from the coefficients in the balanced chemical equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
This indicates that 5 moles of oxygen react with 1 mole of propane to produce 3 moles of carbon dioxide and 4 moles of water. To find the mole to mole ratio between oxygen and carbon dioxide, we look at their coefficients in the balanced equation which are 5 and 3, respectively.
Therefore, the ratio is 5:3. When 0.75 mol of propane is combusted, it reacts with 5/3 times as many moles of oxygen to produce an equal number of moles of carbon dioxide as per the stoichiometric ratios.