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Suppose a radioactive substance decays at a continuous rate of 5.9% per year. How long will it be until only 30% of the original amount remains?

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Final answer:

To determine when only 30% of a radioactive substance with a 5.9% annual decay rate remains, we solve the exponential decay equation and find that it takes approximately 20.4 years.

Step-by-step explanation:

To calculate how long it will take for only 30% of a radioactive substance to remain given a continuous decay rate of 5.9% per year, we use the formula for exponential decay:

A = P * e^(-rt)

Where:

  • A = the amount of substance remaining after time t
  • P = the initial amount of the substance
  • r = the decay rate per unit of time
  • t = the time that has passed
  • e = the base of natural logarithms (approximately 2.71828)

In this scenario, we want to find the time t when A is 30% of P. We set up the equation:

0.30P = P * e^(-0.059t)

To solve for t, we divide both sides by P and take the natural logarithm of both sides:

ln(0.30) = ln(e^(-0.059t))

-1.20397 = -0.059t

Finally, we divide both sides by -0.059 to solve for t:

t = 20.404

Therefore, it will take approximately 20.4 years for 30% of the original amount of the substance to remain.

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