82.1k views
1 vote
Suppose a radioactive substance decays at a continuous rate of 5.9% per year. How long will it be until only 30% of the original amount remains?

1 Answer

4 votes

Final answer:

To determine when only 30% of a radioactive substance with a 5.9% annual decay rate remains, we solve the exponential decay equation and find that it takes approximately 20.4 years.

Step-by-step explanation:

To calculate how long it will take for only 30% of a radioactive substance to remain given a continuous decay rate of 5.9% per year, we use the formula for exponential decay:

A = P * e^(-rt)

Where:

  • A = the amount of substance remaining after time t
  • P = the initial amount of the substance
  • r = the decay rate per unit of time
  • t = the time that has passed
  • e = the base of natural logarithms (approximately 2.71828)

In this scenario, we want to find the time t when A is 30% of P. We set up the equation:

0.30P = P * e^(-0.059t)

To solve for t, we divide both sides by P and take the natural logarithm of both sides:

ln(0.30) = ln(e^(-0.059t))

-1.20397 = -0.059t

Finally, we divide both sides by -0.059 to solve for t:

t = 20.404

Therefore, it will take approximately 20.4 years for 30% of the original amount of the substance to remain.

User Opfau
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories