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Given the balanced chemical equation for the neutralization of hydrochloric acid, HCl, with sodium hydroxide, NaOH, how many moles of NaOH are needed to produce 4.5 moles of water, H2O? HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

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Final answer:

To produce 4.5 moles of water in a neutralization reaction of HCl and NaOH, which have a 1:1 mole ratio, you would need 4.5 moles of NaOH.

Step-by-step explanation:

The given balanced chemical equation for the neutralization reaction, HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l), indicates a 1:1 mole ratio between hydrochloric acid (HCl) and sodium hydroxide (NaOH). To determine the number of moles of NaOH needed to produce 4.5 moles of water (H2O), we can use this mole ratio. As there is a 1:1 ratio of HCl to NaOH, 4.5 moles of water would require an equal amount of NaOH, which is 4.5 moles of NaOH.

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