Final answer:
Part D: The net electric force on an electron at x = 0.200 m is -6.00x10^-11 N.
Part E: The net force is -6.00x10^-11 N. At x = 1.20 m,
Part F: The net force is 1.20x10^-10 N. At x = -0.200 m, the net force is -1.74x10^-10 N.
Step-by-step explanation:
We need to use Coulomb's Law to find the net electric force exerted on an electron at different positions on the x-axis.
To find the force at x = 0.200 m, we can calculate the force due to each charge separately and then sum them up:
First, calculate the force due to the -3.00 nC charge:
F1 = k*q1*q2 / r^2 = (9x10^9 N*m^2/C^2) * (-3.00x10^-9 C) * (1.60x10^-19 C) / (0.200 m)^2 = -2.40x10^-10 N
Next, calculate the force due to the -6.00 nC charge:
F2 = k*q1*q2 / r^2 = (9x10^9 N*m^2/C^2) * (-6.00x10^-9 C) * (1.60x10^-19 C) / (0.200 m - 0.800 m)^2 = 1.80x10^-10 N
Adding up the individual forces, we get the net electric force:
Net force = F1 + F2 = (-2.40x10^-10 N) + (1.80x10^-10 N) = -6.00x10^-11 N
The net electric force on an electron at x = 0.200 m is -6.00x10^-11 N.
Now, let's find the net electric force at x = 1.20 m:
Using the same method as before, we calculate:
F1 = -1.20x10^-10 N
F2 = 2.40x10^-10 N
Net force = F1 + F2 = (-1.20x10^-10 N) + (2.40x10^-10 N) = 1.20x10^-10 N
The net electric force on an electron at x = 1.20 m is 1.20x10^-10 N.
Finally, let's find the net electric force at x = -0.200 m:
Again, using the same method, we calculate:
F1 = -1.20x10^-10 N
F2 = -5.40x10^-11 N
Net force = F1 + F2 = (-1.20x10^-10 N) + (-5.40x10^-11 N) = -1.74x10^-10 N
The net electric force on an electron at x = -0.200 m is -1.74x10^-10 N.