Final answer:
To calculate the vertical velocity at t = 0.25 s, the given values are inserted into the velocity-time relationship formula from Part D, where yo=0.75 m, a=0.95 s-1, and w=6.3 s-1, then calculate to get the velocity.
Step-by-step explanation:
To evaluate the numerical value of the vertical velocity of the car at time t = 0.25 s, we need to substitute the known values into the velocity-time relationship given from Part D. Assuming that the expression for the (vertical) velocity-time relationship for the car is v(t) = a cos(wt) + yo sin(wt), where yo is the initial position, a is a constant with units of s-1, and w is the angular frequency with units of s-1, we can calculate the car's vertical velocity at the specified time.
By inserting the given values into the formula, we get: v(0.25) = (0.95 s-1) cos((6.3 s-1) × (0.25 s)) + (0.75 m) sin((6.3 s-1) × (0.25 s)). Carrying out the calculations will provide us with the car's vertical velocity at t = 0.25 seconds.
To evaluate the numerical value of the vertical velocity of the car at time t = 0.25 s, we can use the expression from Part D. The expression for the (vertical) velocity-time relationship for the car is given by v(t) = a cos(wt) + vo sin(wt), where yo = 0.75 m, a = 0.95 s-1, and w = 6.3 s-1. By substituting these values into the expression, we can calculate the vertical velocity at t = 0.25 s. Let's calculate it: v(0.25) = (0.95 s-1) cos((6.3 s-1) * (0.25 s)) + (0.75 m) sin((6.3 s-1) * (0.25 s))