Question

A 2590 kg test rocket is launched vertically from the launch pad. Its fuel (of negligible mass) provides a thrust force such that its vertical velocity as a function of time is given by v(t)=At+Bt^2 , where A and B are constants and time is measured from the instant the fuel is ignited. The rocket has an upward acceleration of 1.40 m/s^2 at the instant of ignition and, 1.00 s later, an upward velocity of 2.00 m/s

Answer 1

The equation for the rocket's velocity is given as v(t) = At + Bt^2, where A and B are constants and time is measured from the instant the fuel is ignited. The rocket has an upward acceleration of 1.40 m/s^2 at the instant of ignition. However, there seems to be an error in the given information.

Step-by-step explanation:

The equation for the rocket's velocity is given as v(t) = At + Bt2, where A and B are constants and time is measured from the instant the fuel is ignited. The rocket has an upward acceleration of 1.40 m/s2 at the instant of ignition. To find the values of A and B, we can use the given information. We know that at t = 0, the rocket's acceleration is 1.40 m/s2, so substituting this into the equation gives us:

1.40 = A(0) + B(0)2
1.40 = 0 + 0
1.40 = 0

This equation is not possible, so there must be an error in the given information. Please check the equation and values again.