Final answer:
To neutralize 1.324 g of KHP, the calculation based on its molar mass (204.22 g/mol) shows that 0.006482 moles of NaOH are needed due to the one-to-one mole ratio of the neutralization reaction.
Step-by-step explanation:
To determine how many moles of NaOH are necessary to neutralize a solution containing 1.324 g of KHP, we must first convert the mass of KHP to moles. Potassium hydrogen phthalate (KHP, KHC₈H₄O₄) has a molar mass of approximately 204.22 g/mol. Therefore, the moles of KHP are calculated as follows:
moles of KHP = mass in grams ÷ molar mass
= 1.324 g ÷ 204.22 g/mol
= 0.006482 moles of KHP
Since the reaction between KHP and NaOH is a one-to-one mole ratio, an equal number of moles of NaOH are required to neutralize the KHP:
moles of NaOH needed = moles of KHP
= 0.006482 moles
Therefore, 0.006482 moles of NaOH are required to neutralize the given amount of KHP.