32.4k views
3 votes
Let a be a constant. What value of a will make f continuous at x = 3 if f(x) = x/(x² - 9)?

User Fields
by
7.5k points

1 Answer

3 votes

Final answer:

To make the function f continuous at x = 3, we need to ensure that the limit of f(x) as x approaches 3 from both sides is equal. In this case, there is no value of a that will make f continuous at x = 3.

Step-by-step explanation:

To make the function f continuous at x = 3, we need to ensure that the limit of f(x) as x approaches 3 from both sides is equal. In this case, we need to find the value of a such that f(x) is defined and the limit of f(x) exists as x approaches 3.

Let's calculate the limits:

Limit as x approaches 3 from the left side (denoted as x → 3-):

lim x → 3- f(x) = lim x → 3- x/(x² - 9)

Limit as x approaches 3 from the right side (denoted as x → 3+):

lim x → 3+ f(x) = lim x → 3+ x/(x² - 9)

To calculate these limits, substitute x = 3 into the expression and simplify:

lim x → 3- f(x) = lim x → 3- 3/(3² - 9) = lim x → 3- 3/0 which is undefined.

lim x → 3+ f(x) = lim x → 3+ 3/(3² - 9) = lim x → 3+ 3/6 = 1/2.

Since the limits from the left and right sides are not equal, the function f(x) is not continuous at x = 3 for any value of a.

User Dhana
by
9.9k points