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The velocity field for a flow is given by:

V =(5x+6y+7z)^i+(6x+5y+9z)^j+(3x+2y+λz)^k and the density varies as rho=rho0 exp(−2t). In order that the mass is conserved, the value of λ should be ?

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Final answer:

To ensure mass conservation for the given velocity field, we calculate the divergence of the velocity vector and set it to zero. The value of λ that satisfies this condition, with the given variable density, is λ = -10.

Step-by-step explanation:

The student's question involves the application of the mass conservation principle in fluid dynamics to a given velocity field. Mass conservation, also known as the continuity equation in fluid dynamics, implies that for a flow to maintain constant mass, the net outflow or inflow of mass must be zero when the flow is steady. In differential form, the conservation of mass for a fluid with varying density (ρ) is expressed as ∂ρ/∂t + ∇ ⋅ (ρV) = 0, where V is the velocity vector of the flow.

Given that the density of the flow varies as ρ = ρ0 exp(�2t), and the flow is incompressible, to find the value of λ that ensures mass conservation, we must ensure that the divergence of the flow is zero. Therefore, we compute the divergence of the velocity field V and set it equal to zero:

∇ ⋅ V = ∂(5x+6y+7z)/∂x + ∂(6x+5y+9z)/∂y + ∂(3x+2y+λz)/∂z = 5 + 5 + λ = 0

This equation simplifies to 10 + λ = 0, and solving for λ gives us:

λ = -10

In conclusion, the value of λ that ensures mass conservation for the given flow is λ = -10.

User Sargis Isoyan
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