Question

The burner on an electric stove has a power output of 2.0 kW. A 710g stainless steel tea kettle is filled with 20 deg C water and placed on the already hot burner. If it takes 2.70 min for the water to reach a boil, what volume of water, in cm^3, was in the kettle?

Answer 1

The volume of water in the kettle is 770 g.

Step-by-step explanation:

To find the volume of water in the kettle, we need to use the formula: Q = mcΔT, where Q represents the heat transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. First, we need to find the heat transferred by multiplying the power output of the burner by the time it takes for the water to boil: 2.0 kW × 2.70 min = 5.4 kWh. Converting this to joules, we get 5.4 kWh × (3.6 × 10^6 J/kWh) = 1.94 × 10^7 J. Since stainless steel has a specific heat capacity of 0.5 J/g°C, we can rearrange the formula to solve for mass and get: m = Q / (c × ΔT) = 1.94 × 10^7 J / (0.5 J/g°C × (100°C - 20°C)) = 770 g.