Final answer:
Aniline reacts with CH3Cl in the presence of a base to form N-methylaniline, where a CH3 group is attached to the nitrogen, resulting in a secondary amine.
Step-by-step explanation:
The reaction of aniline with CH3Cl (methyl chloride) involves the alkylation of the aniline nitrogen. Aniline, having the formula C6H5NH2, reacts with CH3Cl in the presence of a base to produce N-methylaniline, in which a CH3- group is attached to the nitrogen of the aniline, making it a secondary amine.
Here is an example of the reaction:
- Aniline (C6H5NH2)
- + CH3Cl (methyl chloride)
- + Base
- → N-methylaniline (C6H5NHCH3)
It's essential to note that the provided reaction requires a base to proceed, since it involves the formation of an amide through nucleophilic substitution.