Final answer:
The linear equation of the straight line passing through the point (5, 10) with a slope of 2 is y = 2x + b. Applying the given point to find b, the equation is simplified to y = 2x.
Step-by-step explanation:
To find a linear equation whose graph is a straight line passing through the point (5, 10) with a slope of 2, we can use the point-slope form of a linear equation. The point-slope formula is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.Given the point (5, 10) and the Substitute these values into the point-slope formula:y - 10 = 2(x - 5)Now, simplify and put it into the slope-intercept form y = mx + b:y - 10 = 2x - 10Add 10 to both sides to solve for y:y = 2xThis is the equation of the line passing through the point (5, 10) with a slope of 2.
To find a linear equation in the form y = mx + b with a given slope (m) and a point on the line (x, y), we can use the point-slope form of the equation. The equation is:y - y1 = m(x - x1)Substituting the given values (m = 2, x1 = 5, y1 = 10) into the equation, we get:y - 10 = 2(x - 5)Simplifying the equation, we have:y - 10 = 2x -y = 2xTherefore, the linear equation is y = 2x.