Question

For the reaction shown, compute the theoretical yield of the product (in moles) for each of the following initial amounts of reactants.

Ti(s)+2Cl₂(g) → TiCl₄(s)
A. 8mol Ti, 8mol Cl₂

Answer 1

To calculate the theoretical yield of TiCl4, we identify Cl2 as the limiting reactant in the reaction between 8 moles of Ti and 8 moles of Cl2. The balanced equation shows a 2:1 mole ratio of Cl2 to TiCl4, leading to a theoretical yield of 4 moles of TiCl4.

Step-by-step explanation:

To compute the theoretical yield of the product TiCl4 when 8 mol Ti and 8 mol Cl2 are reacted, we use the balanced chemical equation Ti(s) + 2Cl2(g) → TiCl4(s). This equation tells us that 1 mole of Ti reacts with 2 moles of Cl2 to produce 1 mole of TiCl4. Given the initial amounts, the limiting reactant determines the theoretical yield.

Here, both reactants are present in equal molar amounts, but since it takes 2 moles of Cl2 to react with 1 mole of Ti, Cl2 will be the limiting reactant. As there are 8 moles of Cl2, and the ratio of Cl2 to TiCl4 is 2:1, the theoretical yield of TiCl4 is therefore 4 moles.