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A very long straight wire has charge per unit length 2.60x10^-10C/m. at what distance from the wire is the electric field magnitude equal to 2.10N/C

User JuanR
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1 Answer

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Final answer:

To find the distance from the wire at which the electric field magnitude is equal to 2.10 N/C, use the formula r = k*(lambda)/E.

Step-by-step explanation:

To find the distance from the wire at which the electric field magnitude is equal to 2.10 N/C, we can use the formula for the electric field created by a long straight wire:

E = k*(lambda)/r

Where E is the electric field magnitude, k is the Coulomb's constant (9 x 10^9 Nm^2/C^2), lambda is the charge per unit length (2.60 x 10^-10 C/m), and r is the distance from the wire. Rearranging the equation, we have:

r = k*(lambda)/E

Plugging in the values, we get:

r = (9 x 10^9 Nm^2/C^2) * (2.60 x 10^-10 C/m) / (2.10 N/C)

Calculating this expression will give us the distance from the wire at which the electric field magnitude is equal to 2.10 N/C.

User GCoh
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