Question

Find the second and the third components of a vector n normal to the plane with the equation 8x+11y−7z=10 if the first component of the vector n is equal to 8 .

Answer 1

The second component of the vector n is 8, and the third component is -7.

Step-by-step explanation:

To find the second and third components of a vector n normal to the plane with the equation 8x + 11y - 7z = 10, we can use the fact that the vector n is perpendicular to the plane. The equation of the plane can be written as 8x + 11y - 7z - 10 = 0. Comparing this with the general equation of a plane Ax + By + Cz + D = 0, we can determine the components A, B, and C. The components of the vector n are equal to A, B, and C, respectively. Therefore, the second component of the vector n is 8, and the third component is -7.