Final answer:
To find the position vector of a particle with the given acceleration, initial velocity, and initial position, integrate the acceleration twice. The position vector is given by (19/3)t³ i - e⁻ᵀ j + e⁻ᵗ k + kt + (j + k).
Step-by-step explanation:
To find the position vector of a particle with the given acceleration, initial velocity, and initial position, we can integrate the acceleration function twice.
- Integrate the acceleration function to find the velocity function:
v(t) = ∫(a(t)dt) = ∫(19t i + e⁻ j + e⁻ᵗ k)dt = 19t² i - e⁻ j - e⁻ᵗ k + C₁
- Integrate the velocity function to find the position function:
r(t) = ∫(v(t)dt) = ∫((19t² i - e⁻ j - e⁻ᵗ k + C₁)dt) = (19/3)t³ i - e⁻ᵀ j + e⁻ᵗ k + C₁t + C₂
To find the constants C₁ and C₂, we use the initial velocity and position:
v(0) = k = 0 + C₁ => C₁ = k
r(0) = j + k = 0 + 0 + C₂ => C₂ = j + k
Substituting the values of the constants, we get:
r(t) = (19/3)t³ i - e⁻ᵀ j + e⁻ᵗ k + kt + (j + k)