Final answer:
The function is both continuous and differentiable at x=3.
Step-by-step explanation:
The function given by f(x) is defined differently for x<3 and x≥3. Let's evaluate the function at x=3. For x<3, f(x)=x², so f(3)=3²=9. For x≥3, f(x)=6x-9, so f(3)=6(3)-9=9. Since the function is defined and equal to 9 at x=3 for both cases, the function is continuous at x=3. It is also differentiable at x=3 because both parts of the function have derivatives that exist at x=3. Therefore, the function is both continuous and differentiable at x=3, so the correct answer is (E) both continuous and differentiable.