Question

Mining companies use this reaction to obtain iron from iron ore:

Fe₂O₃(s)+3CO(g) → 2Fe(s)+3CO₂(g)
The reaction of 172 g of Fe₂O₃ with 83.1 g of CO₂ produces 74.3 g of Fe.

Determine the percent yield of solid iron. Express your answer to three significant digits.

Answer 1

The percent yield of solid iron in this reaction is 69.6%.

Step-by-step explanation:

The given chemical equation represents the reaction between iron(III) oxide (Fe₂O₃) and carbon monoxide (CO) to yield solid iron (Fe) and carbon dioxide (CO₂). In the reaction of 172 g of Fe₂O₃ with 83.1 g of CO, 74.3 g of Fe is produced. To determine the percent yield of solid iron, we need to compare the actual yield (74.3 g) to the theoretical yield, which can be calculated using stoichiometry.

To calculate the theoretical yield, we need to convert the given masses of Fe₂O₃ and CO to moles using their molar masses. From the balanced chemical equation, we can determine the mole ratio between Fe₂O₃ and Fe.

Once we have the moles of Fe, we can convert it back to grams using the molar mass of Fe. The percent yield is then calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

The percent yield of solid iron in this reaction is 69.6%.