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A 60-W light bulb radiates electromagnetic waves uniformly in all directions. At a distance of 1.0 m from the bulb, the light intensity is I₀, the average energy density of the waves is u₀, and the rms electric and magnetic field values are E₀ and B₀. respectively.

1. At 2.0 m from the bulb, what is the light intensity?
A. I₀
B. √( I₀/2)
C. I₀/2
D. I₀/4

User T Gupta
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Final answer:

The light intensity at a distance of 2.0 m from a 60-W light bulb, which radiates uniformly, will be one-quarter of the intensity at 1.0 m from it, as light intensity follows the inverse square law. The correct answer is D. I₀ / 4.

Step-by-step explanation:

Light Intensity at Increased Distance

When considering a light source that radiates energy uniformly in all directions, the light intensity observed at a certain distance from the source follows the inverse square law. This law states that the intensity is inversely proportional to the square of the distance from the source. Therefore, if you are at a distance of 1.0 m from the light bulb, and you move to a distance of 2.0 m, the intensity of light (I) will decrease by a factor of (2.0/1.0)², which is 4. Hence, the intensity at 2.0 m will be:

I = I₀ / (2²) = I₀ / 4

Based on this explanation, the correct answer to the question is D. I₀ / 4. At 2.0 m from the bulb, the light intensity will be one-quarter of the intensity at 1.0 m from it.

User Mmar
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