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At 25 °C and 795 Torr, carbon dioxide has a solubility of 0.0356 M in water. What is its solubility at 25 °C and 1690 Torr?

User Mvelay
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Final answer:

Using Henry's law, the solubility of carbon dioxide in water at 25 °C and 1690 Torr is approximately 0.0757 M, which is calculated using the ratio of new pressure to known pressure multiplied by the known solubility.

Step-by-step explanation:

The solubility of carbon dioxide (CO2) in water at a given temperature changes directly with the pressure of the gas above the liquid. This relationship is described by Henry's law, which states that at a constant temperature, the amount of a given gas that dissolves in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.

According to the information given, at 25 °C and 795 Torr, the solubility of CO2 is 0.0356 M. To find the solubility at a higher pressure, we can use the ratio of pressures, since temperature remains constant. The relationship that we will use is:

Solubility at new pressure = Solubility at known pressure × (New pressure / Known pressure)

In this case, the new pressure is 1690 Torr, and the known pressure is 795 Torr. Thus, we calculate the solubility at the new pressure:

Solubility at 1690 Torr = 0.0356 M × (1690 Torr / 795 Torr)

First, find the pressure ratio:

1690 Torr / 795 Torr = 2.1264

Now, calculate the new solubility:

0.0356 M × 2.1264 = 0.0757 M

Therefore, the solubility of carbon dioxide in water at 25 °C and 1690 Torr is 0.0757 M.

User DaniCE
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