Final answer:
The energy of an electron in the n = 7 level of a hydrogen atom is approximately -0.277 eV.
Step-by-step explanation:
The energy of an electron in the n = 7 level of a hydrogen atom can be calculated using the equation En = -13.6 eV/n². Plugging in n = 7, we get:
En = -13.6 eV/7² = -13.6 eV/49 = -0.277 eV
Therefore, the energy of an electron in the n = 7 level of a hydrogen atom is approximately -0.277 eV.