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Evaluate limx→[infinity]​ f(x) and horizontal or slant asymptc (a) f(x)=1−e⁻²ˣ

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Final answer:

The limit of f(x) as x approaches infinity is 1, indicating a horizontal asymptote at y = 1, with no slant asymptote present.

Step-by-step explanation:

The limit of the function f(x) as x approaches infinity, given by f(x) = 1 - e-2x, is 1. The term e-2x approaches zero as x approaches infinity, resulting in the remaining constant value of 1. This suggests the function has a horizontal asymptote at y = 1. As there is no term in f(x) that grows without bound in the form of x times a function of x (which would suggest a slant asymptote), the horizontal asymptote fully describes the behavior of f(x) as x tends toward infinity.

To evaluate the limit of f(x) as x approaches infinity, we can look at the behavior of the function as x gets larger and larger.

For the function f(x) = 1 - e^(-2x), as x approaches infinity, the exponential term e^(-2x) approaches 0. Therefore, the limit of f(x) as x approaches infinity is 1 - 0, which is equal to 1.

There are no horizontal or slant asymptotes for this function.

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