Final answer:
To determine the number of moles of bicarbonate ions, aluminum ions, and oxygen atoms in 66.0 g of aluminum bicarbonate, use the molar masses and stoichiometry of the compound. 0.98 moles of bicarbonate ions, 0.34 moles of aluminum ions, and 0.98 moles of oxygen atoms are present in 66.0 g of aluminum bicarbonate.
Step-by-step explanation:
To determine the number of moles of bicarbonate ions, aluminum ions, and oxygen atoms in 66.0 g of aluminum bicarbonate, we need to use the molar masses and stoichiometry of the compound.
Aluminum bicarbonate (Al(HCO3)3) has a molar mass of 191.0 g/mol.
From the chemical formula, we can see that there are 3 bicarbonate ions, 1 aluminum ion, and 3 oxygen atoms in 1 molecule of aluminum bicarbonate.
Using the molar mass of aluminum bicarbonate, we can calculate the number of moles:
- Bicarbonate ions: (66.0 g) x (1 mol/191.0 g) x (3 ions/1 molecule) = 0.98 mol
- Aluminum ions: (66.0 g) x (1 mol/191.0 g) x (1 ion/1 molecule) = 0.34 mol
- Oxygen atoms: (66.0 g) x (1 mol/191.0 g) x (3 atoms/1 molecule) = 0.98 mol