Final answer:
The electric potential at the center of a ring with a 2 nC charge and a radius of 20 cm is calculated using the formula V = kQ/r. Substituting the given values, the potential is found to be 89.9 V.
Step-by-step explanation:
The electric potential at the center of a ring due to its charged body can be calculated using the formula for the potential of a point charge. Since the charge is uniformly distributed along the ring, the electric potential at the center is the same as if all the charge were concentrated at the center. We use the formula V = kQ/r, where V is the electric potential, k is Coulomb's constant (8.99 x 10^9 N m^2/C^2), Q is the total charge on the ring, and r is the radius of the ring.
Given that the charge Q is 2 nC (2 x 10^-9 C) and the radius r is 20 cm (0.2 m), the electric potential can be calculated as:
V = (8.99 x 10^9 N m^2/C^2) x (2 x 10^-9 C) / 0.2 m
By performing the calculation, we find that:
V = 8.99 x 10^1 V
Therefore, the electric potential at the center of the ring is 89.9 V.