a)The intercepts are x(9,0,0), y(0,+3,0)(0,-3,0) and z-axis(0,0,-1)(0,0,1).
b) Equation of traces are:
For xy trace : x = 9 - y²
For xz- trace: x = 9-9z²
For yz-trace: y²+9z² = 9
How the intercepts and trace equations are determined.
Given
x = 9-y²-9z²
a) To find the intercepts
For x-axis
y = 0, z = 0, substitute into the equation
x = 9 - (0)² - 9(0)²
x = 9
For y-axis
Let x = 0, z = 0 and substitute
0 = 9-y²-9(0)²
y = √9
= +-3
For z-axis
x = 0, y = 0 and substitute
0 = 9 - 0²-9z²
z² = -9/-9
z = √1 = +-1
The intercepts are x(9,0,0), y(0,+-3,0) and z-axis(0,0,+-1)
b) Equation of the traces
For xy-trace
let z = 0
x = 9-y²-9(0)²
x = 9 - y²
For xz- trace
let y = 0
x = 9-0² -9z²
x = 9-9z²
For yz-trace
let x = 0
0 = 9 -y²-9z²
y²+9z² = 9
c) The given equation is
x = 9 -y² - 9z² If the general equation of a elliptical paraboloid is
x = a -by²-cz²
where
a, b and c are constants.
a=9, b = -1 and c = -9
The two dimensional equation is plotted